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A large disc has mass 2kg and radius 0.2...

A large disc has mass 2kg and radius 0.2 m and initial angular velocity 50 rad/s and small disc has mass 4kg and radius 0.1 m and initial angular velocity 200 rad/s both rotating about their common axis. Then the common final angular velocity after discs are in contact is,

A

100 rad/s

B

125 rad/s

C

200 rad/s

D

150 rad/s

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To solve the problem of finding the common final angular velocity after the large and small discs come into contact, we can use the principle of conservation of angular momentum. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Given Data - Mass of the large disc (m1) = 2 kg - Radius of the large disc (r1) = 0.2 m - Initial angular velocity of the large disc (ω1) = 50 rad/s - Mass of the small disc (m2) = 4 kg - Radius of the small disc (r2) = 0.1 m - Initial angular velocity of the small disc (ω2) = 200 rad/s ### Step 2: Calculate the Moment of Inertia for Each Disc The moment of inertia (I) for a disc rotating about its central axis is given by the formula: \[ I = \frac{1}{2} m r^2 \] For the large disc (I1): \[ I_1 = \frac{1}{2} m_1 r_1^2 = \frac{1}{2} \times 2 \, \text{kg} \times (0.2 \, \text{m})^2 \] \[ I_1 = \frac{1}{2} \times 2 \times 0.04 = 0.04 \, \text{kg m}^2 \] For the small disc (I2): \[ I_2 = \frac{1}{2} m_2 r_2^2 = \frac{1}{2} \times 4 \, \text{kg} \times (0.1 \, \text{m})^2 \] \[ I_2 = \frac{1}{2} \times 4 \times 0.01 = 0.02 \, \text{kg m}^2 \] ### Step 3: Calculate the Initial Angular Momentum The initial angular momentum (L_initial) of the system is the sum of the angular momentum of both discs: \[ L_{\text{initial}} = I_1 \omega_1 + I_2 \omega_2 \] \[ L_{\text{initial}} = 0.04 \, \text{kg m}^2 \times 50 \, \text{rad/s} + 0.02 \, \text{kg m}^2 \times 200 \, \text{rad/s} \] \[ L_{\text{initial}} = 2.0 \, \text{kg m}^2/\text{s} + 4.0 \, \text{kg m}^2/\text{s} = 6.0 \, \text{kg m}^2/\text{s} \] ### Step 4: Apply Conservation of Angular Momentum When the discs come into contact, they will rotate together with a common final angular velocity (ω_f). The final moment of inertia (I_f) of the system is the sum of the individual moments of inertia: \[ I_f = I_1 + I_2 = 0.04 \, \text{kg m}^2 + 0.02 \, \text{kg m}^2 = 0.06 \, \text{kg m}^2 \] Using the conservation of angular momentum: \[ L_{\text{initial}} = L_{\text{final}} \] \[ 6.0 \, \text{kg m}^2/\text{s} = I_f \omega_f \] \[ 6.0 = 0.06 \omega_f \] ### Step 5: Solve for the Final Angular Velocity Now, we can solve for ω_f: \[ \omega_f = \frac{6.0}{0.06} = 100 \, \text{rad/s} \] ### Final Answer The common final angular velocity after the discs are in contact is: \[ \omega_f = 100 \, \text{rad/s} \] ---

To solve the problem of finding the common final angular velocity after the large and small discs come into contact, we can use the principle of conservation of angular momentum. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Given Data - Mass of the large disc (m1) = 2 kg - Radius of the large disc (r1) = 0.2 m - Initial angular velocity of the large disc (ω1) = 50 rad/s - Mass of the small disc (m2) = 4 kg - Radius of the small disc (r2) = 0.1 m ...
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