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A dancer spins about himself with an ang...

A dancer spins about himself with an angular speed `omega`, with his arms extended. When he draws his hands in, his moment of inertia reduces by 40% . Then his angular velocity would be

A

`3omega//4`

B

`4omega//5`

C

`5omega//4`

D

`5omega//3`

Text Solution

Verified by Experts

The correct Answer is:
D

`w_(2)=(I omega xx 100)/(60I)=(5omega)/(3)`.
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