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A circular disc P of radius R is made fr...

A circular disc P of radius R is made from an iron plate of thickness t and another disc Q of radius
2R is made from an iron plate of thickness `(t)/(2)`.
The relation between their moments of inertia `I_(p)` and `I_(Q)` about their natural axes is

A

`I_(Q)=4I_(P)`

B

`I_(P)=8I_(Q)`

C

`I_(P)=4I_(Q)`

D

`I_(Q)=8I_(P)`

Text Solution

Verified by Experts

The correct Answer is:
D

`I_(P)=(MR^(2))/(2)`
`(((pi R^(2))t)rho(R^(2)))/(2)=(pi t rho R^(4))/(2)`
`I_(Q)=(MR^(2))/(2)`
`=((pi(2R)^(2)(t//2))rho(2R)^(2))/(2)`
`= (pi t rho(8 R^(4)))/(2)=8I_(P)`.
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