A body of mass `m` slides down an incline and reaches the bottom with a velocity `v`. If the same mass were in the form of a ring which rolls down this incline, the velocity of the ring at the bottom would have been

Options

A. v
B. `v/sqrt2`
C. `sqrt2 v`
D. `(sqrt2)/(5)v`

Answer

B

Explanation

`E_(1)=E_(2)`
`(1)/(2)mv^(2)=(1)/(2)m v_(1)^(2)(1+(k^(2))/(R^(2)))`
`therefore v_(1)^(2)=(v)/(2)`
`v_(1)=(v)/(v_(2))`