Moment of inertia of a uniform circular disc about a diameter is `I`. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be.

Options

A. 5I
B. 3 I
C. 6 I
D. 4 I

Answer

C

Explanation

`I_(d)=(MR^(2))/(4) therefore MR^(2)=4I_(d)`
`I_(T)=(3)/(2)MR^(2)I_(T)=(3)/(2)4I=6I`