The moment of inertia of a thin rod of mass M and length L about an axis perpendicular to the rod at a distance L/4 from one end is

Options

A. `(19ML^(2))/(48)`
B. `(38ML^(2))/(48)`
C. `(7ML^(2))/(48)`
D. `(ML^(2))/(12)`

Answer

C

Explanation

`I_(0)=I_(c )+Mh^(2)=(ML^(2))/(12)+(ML^(2))/(16)`
`=(4ML^(2)+3ML^(2))/(48)=(7ML^(2))/(48)`