If the moment of inertia of a ring about transverse axis passing through its centre is 6 kg `m^(2)`, then the M.I. about a tangent in its plane will be

Options

A. `3kg m^(2)`
B. `9kg m^(2)`
C. `6kg m^(2)`
D. `12 kg m^(2)`

Answer

B

Explanation

`MR^(2)=6 kg m^(2)`
`I_(t)=(3)/(2)MR^(2)`