Three point masses, each of mass 2kg are placed at the corners of an equilateral triangle of side 2m. What is moment of inertia of this system about an axis along one side of a triangle?

Options

A. `2 kg m^(2)`
B. `4 kg m^(2)`
C. `6 kg m^(2)`
D. `8 kg m^(2)`

Answer

C

Explanation

`BD^(2)=AB^(2)-AC^(2)`
`= 4-1`
= 3
`I_(0)=M(BD)^(2)=2xx3=6 kg m^(2)`