Two rings of the same mass and radius are placed such that their centers are at a common point and their planes are perpendicular to each other . The moment of inertia of the system about an axis passing through the diameter of one of the rings is I . Then moment of inertia of one of the ring of the system about the central axis and perpendicular to its plane would be

Options

A. 3I
B. `3I//2`
C. 2I
D. `2I//3`

Answer

A

Explanation

`I=I_(1)+I_(2)`
`=MR^(2)+(MR^(2))/(2)=(3)/(2)MR^(2)=3 I`