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A circular hoop rolls down an inclined p...

A circular hoop rolls down an inclined plane. The ratio of its total energy to rotational kinetic energy is

A

`2:1`

B

`1:3`

C

`3:1`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
A

`(KE_("roll"))/(KE_("rot"))=(1+K^(2)//R^(2))/(K^(2)//R^(2))=(1+1)/(1)=(2)/(1)`.
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