Radius of gyration of disc rotating about an axis perpendicular to its plane passing through through its centre is (If R is the radius of disc)

Options

A. `( R)/(2)`
B. `( R)/(sqrt2)`
C. `( R)/(sqrt3)`
D. `( R)/(3)`

Answer

B

Explanation

`(MR^(2))/(2)=MK^(2) therefore K^(2)=(R^(2))/(2) therefore K = (R )/(sqrt(2))`.