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The total energy of rolling of mass 'm' ...

The total energy of rolling of mass 'm' and radius 'R' is

A

`3//2 mv^(2)`

B

`1//2 mv^(2)`

C

`mv^(2)`

D

`5//2 mv^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`E=(1)/(2)mv^(2)[1+K^(2)//R^(2)]`
`=(1)/(2)mv^(2)[1+1]=mv^(2)`.
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