Displacement 'x' of a simple harmonic oscillator varies with time, according to the differential equation `(d^(2)x//dt^(2))+4x=0`. Then its time period is

Options

A. `pi//2s`
B. `pis`
C. `2pis`
D. `4pis`

Answer

B

Explanation

`(d^(2)x)/(dt^(2))+4x=0`
Compare with standard differenciated equation of linear S.H.M.
`(d^(2)x)/(dt^(2))+omega^(2)x=0`
`omega^(2)=4`
`therefore omega=2`
`T=(2pi)/(omega)=(2pi)/(2)=(pi)/(2)`.