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If a simple harmonic motion is represent...

If a simple harmonic motion is represented by `(d^(2)x)/(dt^(2)) + alphax = 0`, its time period is :

A

`2pialpha`

B

`2pisqrt(alpha`

C

`(2pi)/(alpha)`

D

`(2pi)/(sqrt(alpha))`

Text Solution

Verified by Experts

The correct Answer is:
D
Comparing it with the standard equation of
S.H.M. `(d^(2)x)/(dt^(2))=-omega^(2)x`
We get, `omega^(2)=alpha`
`therefore omega=sqrt(alpha)`
`T=(2pi)/(omega)=(2pi)/(sqrt(alpha))`
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