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1 kg weight is suspended to a weightless...

1 kg weight is suspended to a weightless spring and it has time period T. If now 4 kg weight is suspended from the same spring the time period will be

A

T

B

`T//2`

C

`2T`

D

`4T`

Text Solution

Verified by Experts

The correct Answer is:
C

`T_(1)=2pisqrt((m_(1))/(k))andT_(2)=2pisqrt((m_(2))/(k))`
`(T_(2))/(T_(1))=sqrt((m_(2))/(m_(1)))=sqrt((4)/(1))`
`T_(2)=2T_(1)`
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