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The phase angle between the two projecti...

The phase angle between the two projections of uniform circular motion on any two mutually perpendicular diameter is

A

zero

B

`pi//2`

C

`3pi//4`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
B

`x=Asinomegat" ... (i)"`
`y=Asin(omegat+(pi)/(2))`
`=Acosomegat" ... (ii)"`
Squaring and adding equation (i) and (ii),
`x^(2)+y^(2)=A^(2)(sin^(2)omegat+cos^(2)omegat)`
`x^(2)+y^(2)=A^(2)`
This is standard equation of circle.
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