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The frequency of oscillation of a partic...

The frequency of oscillation of a particle executing SHM with amplitude A and having velocity 'v' at the mean position is

A

`(v)/(2piA)`

B

`(v)/(A)`

C

`(A)/(v)`

D

`(2piA)/(v)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v_(m)=Aomega therefore omega=(v_(m))/(A)`
`2pin=(v_(m))/(A) therefore n=(v_(m))/(2piA)`.
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