A particle executing linear S.H.M. performs 30 oscillations per minute. It's velocity when passing through the middle of its path is 0.157 m/s. The length of the path is

Options

A. 0.2 m
B. 0.5 m
C. 0.1 m
D. 500 cm

Answer

C

Explanation

`v_(m)=Aomega therefore A=(v_(m))/(2pin)`
`A=(0.157)/(2pi(1)/(2))=(1.57xx10^(-1))/(pi)=((pi)/(2)xx1^(-1))/(pi)`
`A=0.5xx10^(-1)`
`L=2A`
`=2xx0.5xx10^(-1)=0.1m`