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A particle executes SHM with an amplitud...

A particle executes `SHM` with an amplitude of `0.2 m`. Its displacement when its phase is `90^(@)` is

A

0.1 m

B

0.2 m

C

0.4 m

D

`0.1//sqrt(2)m`

Text Solution

Verified by Experts

The correct Answer is:
B
`y=Asin(omegat+phi)=0.2sin90^(@)=0.2m`
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