The velocity of the particle midway between mean and extreme position, performing S.H.M. is

Options

A. `A omega`
B. `(sqrt(3))/(2)A omega`
C. `(2)/(sqrt(2))A omega`
D. `sqrt(3)A omega`

Answer

B

Explanation

`v_(m)=omegasqrt(A^(2)-x^(2))=omegasqrt(A^(2)-(A^(2))/(4))`
`=omegasqrt((4A^(2)-A^(2))/(4)`
`=omegasqrt((3A^(2))/(4))=sqrt(3)/(2)Aomega`