The displacement x is in centimeter of an oscillating particle varies with time t in seconds as x = 2 cos `[0.05pi t+(pi//3)]`. Then the magnitude of the maximum acceleration of the particle will be

Options

A. `(pi)/(2)cm//s^(2)`
B. `(pi)/(4)cm//s^(2)`
C. `(pi^(2))/(200)cm//s^(2)`
D. `(pi^(2))/(4)cm//s^(2)`

Answer

C

Explanation

Acceleration max `=(Aomega^(2))`
`=2(0.05pi)^(2)`
`=2xx25 pi^(2)xx10^(-4)`
`=50pi^(2)xx10^(-4)`
`=0.5pi^(2)xx10^(-2)`
`=(pi^(2))/(200)`