The average velocity of a particle execu...

The average velocity of a particle executing SHM with an amplitude A and angular frequency `omega` during one oscillation is

`omegaA`

`(omegaA)/(2)`

`2omegaA//pi`

zero

Text Solution

Verified by Experts

The correct Answer is:

`v_(1)=omegasqrt(A^(2)-x_(1)^(2))`
`3=omegasqrt(25-16)`
`3=3omega" "therefore omega=1`
`T=(2pi)/(omega)=(2pi)/(1)=6.28s`

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