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A particle executing SHM of amplitude ...

A particle executing SHM of amplitude 4 cm and `T=4 s` .The time taken by it to move from positive extreme position to half the amplitude is

A

0.5 s

B

`2//3` s

C

0.75 s

D

1 s

Text Solution

Verified by Experts

The correct Answer is:
B
`x=Acosomegat" "(A)/(2)=Acosomegat`
`thereforeomegat=cos^(-1)((1)/(2))" "therefore (2pi)/(T)t=(pi)/(3)`
`t=(4)/(3xx2)=(2)/(3)s`
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