If a particle executing S.H.M. with amplitude A and maximum velocity vo, then its speed at displacement A/2 is

Options

A. `13.4 % v_(m)`
B. `86.6 % v_(m)`
C. `37.5 % v_(m)`
D. `66.67 % v_(m)`

Answer

B

Explanation

`v=omegasqrt(A^(2)-(A^(2))/(4))v=Aomega(sqrt(3))/(2)`
`=Aomegaxx0.866=86.6%v_(m)`