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A particle executing simple harmonic mot...

A particle executing simple harmonic motion has an amplitude of 6 cm . Its acceleration at a distance of 2 cm from the mean position is `8 cm/s^(2)` The maximum speed of the particle is

A

`8 cm//s`

B

`12 cm//s`

C

`16 cm//s`

D

`24 cm//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(m)=Aomega" "a=Aomega^(2)`
`therefore omega^(2)=a//A`
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