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A particle executes S.H.M. of period 1.2...

A particle executes S.H.M. of period 1.2 s and amplitude 8 cm. What is the time taken to travel 2.344 cm from the positive extremity?

A

0.17 s

B

1 s

C

0.15 s

D

0.7 s

Text Solution

Verified by Experts

The correct Answer is:
C
`A-2.344=Acosomegat`
`cosomegat=(5.656)/(8)=0.707`
`omegat=cos^(-1)(0.707)`
`(2pi)/(T)t=(pi)/(4)`
`t=0.15s`
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