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The maximum speed of a particle executin...

The maximum speed of a particle executing S.H.M. is 1 m/s and its maximum acceleration is`1.57 m// sec^(2)` . The time period of the particle will be

A

`1//1.57 s`

B

`1.57 s`

C

2 s

D

4 s

Text Solution

Verified by Experts

The correct Answer is:
D
`omega=(a_(m))/(v_(m))=((pi)/(2))/(1)=(pi)/(2)`
`T=(2pi)/(omega)=(2pi)/((pi)/2)=4s`
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