The acceleration of a particle executing SHM at a distance of 3 cm from equilibrium position is `5 cm//s^(2)`. Its acceleration at a distance of 2 cm from equilibrium position is

Options

A. `10//3 cm//s^(2)`
B. `10 cm//s^(2)`
C. `7.5 cm//s^(2)`
D. `4.5 cm//s^(2)`

Answer

A

Explanation

`(a_(2))/(a_(1))=(x_(2))/(x_(1))=(2)/(3)`
`a_(2)=(2)/(3)a_(1)=(2)/(3)xx5=(10)/(3)cm//s^(2)`.