A particle executing SHM has a frequency...

A particle executing SHM has a frequency of 10 Hz when it crosses its equilibrium position with a velocity of `2pi m//s`. Then the amplitude of vibration is

0.1 m

0.2 m

0.4 m

1 m

Text Solution

Verified by Experts

The correct Answer is:

`v_(m)=Aomega`
`therefore A=(v_(m))/(2pin)=(2pi)/(2pixx10)=0.1m`

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