The period of a simple harmonic oscillator is 2 s. If it crosses mean position at an instant. The time after which its displacement from the mean position will be half of the amplitude is.

Options

A. `(1//8)s`
B. `(1//6)s`
C. `(1//4)s`
D. `(1//2)s`

Answer

B

Explanation

`x=Asinomegat`
`(1)/(2)A=Asinomegat`
`omegat=sin^(-1)((1)/(2))=(pi)/(6)`
`(2pi)/(T)t=(pi)/(6)`
`t=(T)/(12)=(2)/(12)=(1)/(6)s`