Velocity of a simple harmonic oscillator in the mean position is `v_(0)`. If its amplitude is doubled, without changing its period of oscillation, its velocity in the mean position will be

Options

A. `v_(0)//(2)`
B. `2v_(0)`
C. `v_(0)`
D. `v_(0)//4`

Answer

B

Explanation

`A_(2)=2A_(1),v_(2)=?`
`(v_(2))/(v_(1))=(A_(2)omega)/(A_(1)omega)=(2A)/(A)=2`
`v_(2)=2v_(0)`