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A body executing S.H.M. has a period of ...

A body executing S.H.M. has a period of 3 s under one force and 4 s under another force. Then time period under the action of both the forces together in the same direction is

A

1.2 s

B

2.4 s

C

3.6 s

D

4.8 s

Text Solution

Verified by Experts

The correct Answer is:
B
`T=(T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))=(3xx4)/(sqrt(9xx16))=(3xx4)/(5)`
`=(12)/(5)=2.4s`
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