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A simple harmonic oscillator has its dis...

A simple harmonic oscillator has its displacement varying as x = 15 sin `(2pit+pi//4)` metre. Then its initial displacement is

A

15 m

B

`15//sqrt(2) m`

C

`15 sqrt(2) m`

D

`7.5 m`

Text Solution

Verified by Experts

The correct Answer is:
B

`x=15sin(2pit+(pi)/(4))`
`=15sin(2pixx0+(pi)/(4))`
`=15sin.(pi)/(4)`
`=15xx(1)/(sqrt(2))=(15)/(sqrt(2))m`
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