Home
Class 12
PHYSICS
Two simple harmonic motions are given by...

Two simple harmonic motions are given by `y_(1) = a sin [((pi)/(2))t + phi]` and `y_(2) = b sin [((2pi)/( 3))t + phi]`. The phase difference between these after `1 s` is

A

`pi`

B

`pi//2`

C

`pi//4`

D

`pi//6`

Text Solution

Verified by Experts

The correct Answer is:
D
`phi_(2)-phi_(1)=((2pi)/(3)t-(pi)/(2)t)=((2pi)/(3)-(pi)/(2))xx1`
`=((4pi-3pi)/(6))=(pi)/(6)`
Promotional Banner

Topper's Solved these Questions

  • MHT-CET 2016

    NIKITA PUBLICATION|Exercise COMMUNICATION SYSTEMS|1 Videos

  • QUESTION PAPER - MH-CET 2018

    NIKITA PUBLICATION|Exercise MCQ|50 Videos

Similar Questions

Explore conceptually related problems

Two S.H.Ms are given by y_(1) = a sin ((pi)/(2) t + (pi)/(2)) and y_(2) = b sin ((2pi)/(3) t + (pi)/(2)) . The phase difference between these after 1 second is

Two waves are given by y_(1) = a sin (omega t - kx) and y_(2) = a cos (omega t - kx) . The phase difference between the two waves is

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Statement-I : Two simple harmonic motions are given by y_(1) = 10sin (3pi t+(pi)/(4)) and y_(2) = 5(sin 3pit +sqrt(3) cos 3pi t) . These have amplitudes in the ratio 1:1 . Statement-II : y_(1) & y_(2) respresents two waves of amplitudes 5 & 5sqrt(3) . So the resultant amplitude is 10 .

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

The simple harmonic vibrations of two particles are y_(1)= 5sin (100t) and y_(2) = 4 cos (100t + pi/4) . The phase difference between both particles is

Two partical A and B execute simple harmonic motion according to the equation y_(1) = 3 sin omega t and y_(2) = 4 sin [omega t + (pi//2)] + 3 sin omega t . Find the phase difference between them.

Two simple harmonic motions A and B are given respectively by the following equations. y_(1)=asin[omegat+(pi)/(6)] y_(2)=asin[omegat+(3pi)/(6)] Phase difference between the waves is

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of

NIKITA PUBLICATION-OSCILLATIONS -MCQ
  1. The displacement equation of a particle performing S.H.M. is x = 10 si...

    Text Solution

    |

  2. If the displacement of a particle executing S.H.M. is given by x = 0.2...

    Text Solution

    |

  3. Two simple harmonic motions are given by y(1) = a sin [((pi)/(2))t + p...

    Text Solution

    |

  4. The displacement of a simple harmonic oscillator is, x = 5 sin (pit//3...

    Text Solution

    |

  5. A particle oscillates, according to the equation x = 5 cos (pit//2) m....

    Text Solution

    |

  6. A particle executing S.H.M. is given by x=10sin(8t+pi//3)m. Its velo...

    Text Solution

    |

  7. The displacement equation of an oscillator is given by x = 5 sin (2pit...

    Text Solution

    |

  8. The acceleration of a simple harmonic oscillator is 1 m//s^(2) when it...

    Text Solution

    |

  9. The displacement of a simple harmonic oscillator is given by x = 4 cos...

    Text Solution

    |

  10. A particle executes SHM along a straight line so that its period is 12...

    Text Solution

    |

  11. Two bodies of equal mass are hung from two light vertical springs. The...

    Text Solution

    |

  12. Starting from the origin a body osillates simple harmonicall with a pe...

    Text Solution

    |

  13. A particle of mass 0.3 kg subject to a force F=-kx with k=15N//m. What...

    Text Solution

    |

  14. The displacement of a SHO is given by y = 2 sin (2pit+pi//4)m. The rat...

    Text Solution

    |

  15. A particle is executing SHM with an amplitude of 2 m. The difference i...

    Text Solution

    |

  16. The maximum velocity and maximum acceleration of a particle executing ...

    Text Solution

    |

  17. A particle is executing SHM with and frequency of (1)/(8) Hz. If it st...

    Text Solution

    |

  18. A particle executes SHM with a time period of 8 s. It is starts from t...

    Text Solution

    |

  19. If the maximum speed of a SHO is pi ms^(-1). Its average speed during ...

    Text Solution

    |

  20. A particle executing SHM passes through the mean position with a veloc...

    Text Solution

    |