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A particle executing SHM passes through ...

A particle executing SHM passes through the mean position with a velocity of `4 ms^(-1)`. The velocity of the particle at a point where the displacement is half of the amplitude is

A

`2 ms^(-1)`

B

`2sqrt(3)ms^(-1)`

C

`sqrt(3)ms^(-1)`

D

`1ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`V=(Aomegasqrt(3))/(2)=(4sqrt(3))/(2)=2sqrt(3)ms^(-1)`
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NIKITA PUBLICATION-OSCILLATIONS -MCQ
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