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A particle executes SHM along x-axis wit...

A particle executes SHM along x-axis with an amplitude A, time period T with origin as the mean position. At t = 0, if the particle starts in the +ve x-direction from the origin the minimum time in which it will be at `x=-A//2` will be

A

`(T)/(12)`

B

`(T)/(6)`

C

`(T)/(4)`

D

`(7T)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
D
`-(A)/(2)=Asinomegat,sinomegat=-(1)/(2)impliesomegat=(7pi)/(6)`
`t=(7T)/(12)`.
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