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An object is attched to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is `15cm//s` and the period is `628` milli seconds. The amplitude of the motion in centimetres is

A

`3.0`

B

`2.0`

C

`1.5`

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`v_(m)=15cm//s, T=6.28xx10^(-1)s`
`v_(m)=Aomega`
`A=(v_(m))/(omega)=(15)/(2pi)xxT`
`=(15xx6.28xx10^(-1))/(6.28)=15xx10^(-1)=1.5cm`.
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