If a particle performing S.H.M. from the mean position of amplitude 'A' and period 'T', then the lapse of fraction of period in `(7//8)^(th)` oscillation will be

Options

A. `(T)/(12)`
B. `(T)/(6)`
C. `(11)/(12)T`
D. `(7)/(8)T`

Answer

C

Explanation

In `(1//8)^(th)` oscillation, time required is `(T)/(12)`
`therefore (7//8)^(th)` oscillation the time required is `11T//12`.