The potential energy of a particle with displacement X is `U(X)`. The motion is simple harmonic, when (K is a positive constant)

Options

A. `u=(-kx^(2))/(2)`
B. `u=(1)/(2)kx^(2)`
C. `u=k`
D. `u=kx`

Answer

B

Explanation

`P.E.=(1)/(2) m omega^(2)x^(2) " As" (1)/(2) m omega^(2)=`const.
`therefore P.E. prop x^(2)=k x^(2)`