A particle of mass m executes SHM with amplitude A and frequency n. The average energy in one time period is

Options

A. `pi^(2)mn^(2)A^(2)`
B. `2pi^(2)mn^(2)A^(2)`
C. `pi^(2)m^(2)n^(2)A^(2)`
D. `2pimn^(2)A^(2)`

Answer

B

Explanation

`E=(1)/(2) m omega^(2)x^(2)A^(2)=(1)/(2) m(2pin)^(2)A^(2)`
`=2pi^(2)MN^(2)a^(2)`.