A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilinrium to the end is.

Options

A. `pi^(2)mn^(2)A^(2)`
B. `2pi^(2)mn^(2)A^(2)`
C. `(pi^(2)mn^(2)A^(2))/(2)`
D. zero

Answer

A

Explanation

`(ke_("max")+0)/(2)=(1)/(2) ((1)/(2)m omega^(2) A^(2))`
`=(1)/(4) m (2pin)^(2)A^(2)`
`=pi^(2)mn^(2)A^(2)`.