The ratio of potential energy to kinetic energy of a particle performing S.H.M. at midway between mean and extreme position is

Options

A. `3 : 1`
B. `1 : 3`
C. `6 : 9`
D. `4 : 3`

Answer

B

Explanation

`(P.E.)/(K.E.)=((1)/(2)k(A^(2))/(4))/((1)/(2)k(A^(2)-(A^(2))/(4)))=(A^(2))/(4)xx(4)/(3A^(2))=(1)/(3)`