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Ratio of kinetic energy to potential ene...

Ratio of kinetic energy to potential energy of an oscillator when it is at distance `1//N` times of amplitude from mean positions in

A

`n^(2)`

B

`n^(2)+1`

C

`1//n^(2)`

D

`n^(2)-1`

Text Solution

Verified by Experts

The correct Answer is:
D

`(K.E.)/(P.E.)=((1)/(2)momega^(2)(A^(2)-x^(2)))/((1)/(2)momega^(2)x^(2))`
`=(A^(2)-x^(2))/(x^(2))=(A^(2)-(A^(2))/(n^(2)))/((1)/(n^(2))A^(2))=n^(2)-1`
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