The total energy of simple harmonic oscillator is E and amplitude is 'A'. It the kinetic energy is 3E/4 without altering the amplitude. The displacement of the oscillator is

Options

A. `A//2`
B. `3A//4`
C. `2 A`
D. `4 A`

Answer

A

Explanation

`T.E.=K.E.+P.E.`
`E=(3)/(4)E+(1)/(2)momega^(2)x^(2)`
`(1)/(4)E=(1)/(2)momega^(2)x^(2)`
`(1)/(4)xx(1)/(2)momega^(2)A^(2)=(1)/(2)momega^(2)x^(2)`
`therefore x^(2)=(A^(2))/(4)`
`x=(A)/(2)`