A particle of mass 1 kg is moving in SHM with an amplitude 0.02 m and a frequency of 60 Hz. The maximum force (in N) acting on the particle is

Options

A. `2.88 pi^(2)N`
B. `28.8 pi^(2)N`
C. `288 pi^(2)N`
D. `2880 pi^(2)N`

Answer

C

Explanation

`F=KA=momega^(2)A`
`=1xx(4pi^(2))/(T^(2))xx2xx10^(-2)`
`=(4pi^(2)xx2xx10^(-2))/(((1)/(60))^(2))=3600xx8pi^(2)xx10^(-2)`
`=288pi^(2)`