A particle executing SHM has a total energy E. Another particle of twice the mass of the first particle executes SHM with 4 times the frequency and twice the amplitude of the first. Its total energy is

Options

A. `E//2`
B. 32 E
C. 64 E
D. 128 E

Answer

D

Explanation

`E=2pi^(2)mn^(2)A^(2)`
`E=2pi^(2)(2m)(4n^(2))(2A^(2))`
`(E)/(E')=(1)/(128)`
`E'=128E`