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The displacement of a particle performin...

The displacement of a particle performing S.H.M. is x = 0.1 sin `(5pit)+0.4cos(5pit)m`.
Then the speed of the particle at 0.1 s will be

A

`82pi`

B

`2pi`

C

`pi`

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
`x=0.1sin5pit+0.4cos5pit`
`v=(dx)/(dt)=0.1xx5picos5pit-0.4xx5pisin5pit`
`=0.5pixxcos.(pi)/(2)-2pisin.(pi)/(2)`
`=0.5xxpixx0-2pixx1`
`=-2pim//s`
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