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The displacement of a particle executing...

The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

A

`(300)/(pi)Hz`

B

`(300)/(2pi)Hz`

C

`(150)/(2pi)Hz`

D

`300 Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=0.34sin(300t+0.68)m`
`omega=300`
`2pin=300`
`n=(150)/(pi)`
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