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The displacement of a particle in S.H.M....

The displacement of a particle in S.H.M. is given by `x = sinomegat+sqrt(3)cosomegatm`. Then at t = 0 its displacement in metres is

A

0.5

B

`sqrt(3)`

C

1

D

`1//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=sinomegat+sqrt(3)cosomegat`
`=sinomegaxx0+sqrt(3)cosomegatxx0`
`=sin(0)+sqrt(3)xxcos(0)=0+sqrt(3)xx1`
`=sqrt(3)`
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