If a simple pendulum is taken to place where g decreases by 2%, then the time period

Options

A. increase by 2 %
B. increase by 1 %
C. increase by 4 %
D. decrease by 1 %

Answer

B

Explanation

`(T_(2))/(T_(1))=sqrt((g_(1))/(g_(2)))=sqrt((g_(1))/((1-0.02)g_(1)))`
By using Binomial theorem
`therefore (T_(2))/(T_(1))=(1-0.02)^(-1//2)=1+(1)/(2)xx0.02`
`(T_(2))/(T_(1))-1=0.01`
`(T_(2)-T_(1))/(T_(1))%=1%`